4.9t^2-16.7t-75=0

Solution for 4.9t^2-16.7t-75=0 equation:

4.9t^2-16.7t-75=0

a = 4.9; b = -16.7; c = -75;
Δ = b2-4ac
Δ = -16.72-4·4.9·(-75)
Δ = 1748.89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16.7)-\sqrt{1748.89}}{2*4.9}=\frac{16.7-\sqrt{1748.89}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16.7)+\sqrt{1748.89}}{2*4.9}=\frac{16.7+\sqrt{1748.89}}{9.8}
$